C Program to Store Information of Students Using Structure

In this example, you will learn to store the information of 5 students by using an array of structures.

To understand this example, you should have the knowledge of the following C programming topics:

Store Information in Structure and Display it

#include <stdio.h>
struct student {
    char firstName[50];
    int roll;
    float marks;
} s[10];

int main() {
    int i;
    printf("Enter information of students:\n");

    // storing information
    for (i = 0; i < 5; ++i) {
        s[i].roll = i + 1;
        printf("\nFor roll number%d,\n", s[i].roll);
        printf("Enter first name: ");
        scanf("%s", s[i].firstName);
        printf("Enter marks: ");
        scanf("%f", &s[i].marks);
    }
    printf("Displaying Information:\n\n");

    // displaying information
    for (i = 0; i < 5; ++i) {
        printf("\nRoll number: %d\n", i + 1);
        printf("First name: ");
        puts(s[i].firstName);
        printf("Marks: %.1f", s[i].marks);
        printf("\n");
    }
    return 0;
}

Output

Enter information of students: 

For roll number1,
Enter name: Tom
Enter marks: 98

For roll number2,
Enter name: Jerry
Enter marks: 89
.
.
.
Displaying Information:

Roll number: 1
Name: Tom
Marks: 98
.
.
.

In this program, a structure student is created. The structure has three members: name (string), roll (integer) and marks (float).

Then, we created an array of structures s having 5 elements to store information of 5 students.

Using a for loop, the program takes the information of 5 students from the user and stores it in the array of structure. Then using another for loop, the information entered by the user is displayed on the screen.