 # C++ Program to Check Whether Number is Even or Odd

In this example, if...else statement is used to check whether a number entered by the user is even or odd.

To understand this example, you should have the knowledge of the following C++ programming topics:

Integers which are perfectly divisible by 2 are called even numbers.

And those integers which are not perfectly divisible by 2 are not known as odd number.

To check whether an integer is even or odd, the remainder is calculated when it is divided by 2 using modulus operator %. If remainder is zero, that integer is even if not that integer is odd.

## Example 1: Check Whether Number is Even or Odd using if else

``````#include <iostream>
using namespace std;

int main()
{
int n;

cout << "Enter an integer: ";
cin >> n;

if ( n % 2 == 0)
cout << n << " is even.";
else
cout << n << " is odd.";

return 0;
}
``````

Output

```Enter an integer: 23
23 is odd.```

In this program, if..else statement is used to check whether `n%2 == 0` is true or not. If this expression is true, n is even if not n is odd.

You can also use ternary operators ?: instead of if..else statement. Ternary operator is short hand notation of if...else statement.

## Example 2: Check Whether Number is Even or Odd using ternary operators

``````#include <iostream>
using namespace std;

int main()
{
int n;

cout << "Enter an integer: ";
cin >> n;

(n % 2 == 0) ? cout << n << " is even." :  cout << n << " is odd.";

return 0;
}``````