C++ Program to Display Factors of a Number

Example to find all factors of an integer (entered by the user) using for loop and if statement.

To understand this example, you should have the knowledge of the following C++ programming topics:

This program takes a positive integer from an user and displays all the factors of that number.


Example: Display all Factors of a Number

#include <iostream>
using namespace std;

int main()
{
    int n, i;

    cout << "Enter a positive integer: ";
    cin >> n;

    cout << "Factors of " << n << " are: " << endl;  
    for(i = 1; i <= n; ++i)
    {
        if(n % i == 0)
            cout << i << endl;
    }

    return 0;
}

Output

Enter a positive integer: 60
Factors of 60 are: 1 2 3 4 5 6 12 15 20 30 60

In this program, an integer entered by user is stored in variable n.

Then, for loop is executed with an initial condition i = 1 and checked whether n is perfectly divisible by i or not. If n is perfectly divisible by i then, i will be the factor of n.

In each iteration, the value of i is updated (increased by 1).

This process goes until test condition i <= n becomes false,i.e., this program checks whether number entered by user n is perfectly divisible by all numbers from 1 to n and all displays factors of that number.